Java switch statement

[Reason7194]

Hello everyone, i am trying my hand at a switch statement in my java program. I am using the NetBeans IDE and when i write in the syntax for the switch statement, NetBeans tells me thought i have an error on the line. I honestly do not know what i have done wrong with switch statement. If anyone could give me advice on how to solve the problem that would be wonderful.

Switch statement:

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switch( choice = (char)System.in.read());

Here is the full code of my program ( that is not finished yet )

Code: Select all

/**
*
* @author Administrator
*/
import java.io.*;


public class Test {

public static void main(String[] args)throws IOException{
    char choice;

    System.out.println("Pick one of the following");
    System.out.println("A for Apple");
    System.out.println("B for Bapple");
    System.out.println("C for Capple");
    System.out.flush();

    try{
        switch( choice = (char)System.in.read());
            {
            case 'A': System.out.println("You have picked Apple");

            break;

            case 'B': System.out.println("You have picked Bapple");

            break;

            case 'C': System.out.println("You have picked Capple");

            break;
       
       
       catch(IOException){
           System.out.println("An IO exception has been called");
           
              }
            }
           }
         }
       }


[Assassian360]

Remove the semicolon (;) from the end of that line.

[Reason7194]

Thanks, that was a really simple error..i should have saw that.

Now my problem is that it is saying my try-catch is wrong. Why?

Updated project syntax:

Code: Select all

import java.io.*;


public class Test {

public static void main(String[] args)throws IOException{
    char choice;

    System.out.println("Pick one of the following");
    System.out.println("A for Apple");
    System.out.println("B for Bapple");
    System.out.println("C for Capple");
    System.out.flush();

    try{
        switch( choice = (char)System.in.read())
            {
            case 'A': System.out.println("You have picked Apple");

            break;

            case 'B': System.out.println("You have picked Bapple");

            break;

            case 'C': System.out.println("You have picked Capple");

            break;

        defult: System.out.println("Invalid");
       
       catch(IOException){
           System.out.println("Invaled"));

       }
       }
        }

        }
}

[sanddbox]

It was a mix between your curly braces being screwed up, a lot of misspellings (it's default, not defult, for example), and you not giving a name to your IOException object. Here you go:

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package helpnoobagain;

import java.io.*;

public class Test {

    public static void main(String[] args) throws IOException {
        char choice;

        System.out.println("Pick one of the following");
        System.out.println("A for Apple");
        System.out.println("B for Bapple");
        System.out.println("C for Capple");
        System.out.flush();
        try {
            switch (choice = (char) System.in.read()) {
            case 'A':
                System.out.println("You have picked Apple");

                break;

            case 'B':
                System.out.println("You have picked Bapple");

                break;

            case 'C':
                System.out.println("You have picked Capple");

                break;

            default:
                System.out.println("Invalid");
            }
        } catch (IOException e) {
            System.out.println("Invalid");
        }
    }
}


EDIT: Ignore the package statement

[Reason7194]

Ah, thanks. Question: Why must i set the IOException to a character?

[sanddbox]

Ah, thanks. Question: Why must i set the IOException to a character?

Remember that in Java, everything is an object. IOException is...well, no exception. You're asking for an IOException object to be passed to your catch block, so you're going to need to give it a name, just as you name any other variable.

Here's an example that actually uses the IOException object:

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catch (IOException e) {
            e.printStackTrace();
        }

Remember, "e" is just the name we gave the IOException object; it could be anything.

[Reason7194]

O ok, thank you. I understand now. Silly mistake i had made then.

-Thanks everyone

[yourmysin]

Ah, thanks. Question: Why must i set the IOException to a character?

Remember that in Java, everything is an object. IOException is...well, no exception.

I see what you did there

[MarkIntelhunter99]

I checked out your source code i found some files that are needed not for the program.

here's the debugged one and at the same time, i was having fun improving it a little bit.^_^.

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/**
*
* @author Administrator
*/
import java.io.*;


public class Test2 {

public static void main(String[] args)throws IOException{
    char choice;
   boolean test = false;
   do{
    System.out.println("Pick one of the following");
    System.out.println("A for Apple");
    System.out.println("B for Bapple");
    System.out.println("C for Capple");
    System.out.flush();

        switch( choice = (char)System.in.read())
            {
            case 'A': System.out.println("You have picked Apple");
         test = true;
            break;

            case 'B': System.out.println("You have picked Bapple");
         test = true;
            break;

            case 'C': System.out.println("You have picked Capple");
         test = true;
            break;

            default: System.out.println("Error");
            break;
            }



       }while (test != true);
   }
}